Q14. 2(sin6 θ + cos6 θ) – 3(sin4 θ + cos4 θ) is equal to

Question

(a) 0
(b) 6
(c) -1
(d) None of these

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swatiqna 3 years 2021-12-23T11:00:42+00:00 1 Answer 9 views Enlightened 0

Answer ( 1 )

    0
    2021-12-23T11:01:06+00:00

    Answer: (c) -1
    2(sin6θ+cos6θ)−3(sin4θ+cos4θ)+1
    =2{(sin2θ+cos2θ)3−3sin2θcos2θ(sin2
    θ+cos2θ)}−3(sin2θ+cos2θ)2−2(sin2θc
    os2θ)}+1
    We know, [sin2x+cos2x=1]
    =2{1−3sin2θcos2θ}−3{1−2sin2θcos2θ
    }+1

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