Q24. The value of (tan1° tan2° tan3° … tan89°) is
Question
(A) 0
(B) 1
(C) 2
(D)1/2
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Class 10 Maths
3 years
2021-12-23T11:34:43+00:00
2021-12-23T11:34:43+00:00 1 Answer
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Answer ( 1 )
Answer: (B)
Explanation: This can be written as,
(tan1° tan2° tan3° … tan89°)
(tan1° tan2° tan3° ……. tan44°
tan45° tan46° …..
tan87°tan88°tan89°)
= [tan1° tan2° tan3° ……. tan44°
tan45° tan (90 – 44)° ….. tan(90° –
3) tan (90° – 2) tan (90° – 1)]
= (tan1° tan2° tan3° ……. tan44°
tan45° cot 44° ….. cot3° cot2° cot
1°)
= 1