Q26. A box of 600 bulbs contains 12 defective bulbs. One bulb is taken out at random from this box. Then the probability that it is non- defective bulb is:

Question

(A) 143/150
(B) 147/150
(C) 1/25
(D) 1/50

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swatiqna 3 years 2021-12-28T13:40:55+00:00 1 Answer 22 views Enlightened 0

Answer ( 1 )

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    2021-12-28T13:41:54+00:00

    Answer: (B)
    Explanation:
    P (non-defective bulb) = 1 – P
    (Defective bulb)
    = 1 – (12/600)= (600 – 12)/600
    = 588/600
    = 147/150

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