Q15. If cos (81 + θ)° = sin(k3 – θ)° where θ is an acute angle, then the value of k is

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Q15. If cos (81 + θ)° = sin(k3 – θ)° where θ is an acute angle, then the value of k is

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(a) 18°
(b) 27°
(c) 9°
(d) 81°

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Class 10 Maths swatiqna 3 years 2021-12-23T11:02:15+00:00 2021-12-23T11:02:15+00:00 1 Answer 26 views Enlightened 0

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swatiqna Enlightened · Answer 1 · 2021-12-23T11:03:01+00:00

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2021-12-23T11:03:01+00:00 December 23, 2021 at 11:03 am

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Answer: (b) 27°
Explanation: cos theta = sin (90 –
theta) for theta <= 90
so using this
cos(81 + theta) = sin (k/3- theta)
sin ( 90 – 81 – theta) = sin ( k/3 –
theta)
sin( 9- theta) = sin (k/3 – theta)
comparing now angles
9- theta = k/3 – theta
k/3 = 9 -theta + theta
k/3 = 9
k= 9*3
k = 27

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Q15. If cos (81 + θ)° = sin(k3 – θ)° where θ is an acute angle, then the value of k is