Sides of two similar triangles are in the ratio 4: 9. Areas of these triangles are in the ratio
Question
(a)2: 3
(b)4: 9
(c)81: 16
(d)16: 81
in progress
0
Class 10 Maths
3 years
2021-12-29T13:23:45+00:00
2021-12-29T13:23:45+00:00 1 Answer
8 views
Enlightened 0
Answer ( 1 )
Answer: d
Explanation: Let ABC and DEF
are two similar triangles, such
that,
ΔABC ~ ΔDEF
And AB/DE = AC/DF = BC/EF =
4/9
As the ratio of the areas of these
triangles will be equal to the
square of the ratio of the
corresponding sides,
∴ Area(ΔABC)/Area(ΔDEF) =
AB2/DE2
∴ Area(ΔABC)/Area(ΔDEF) =
(4/9)2 = 16/81 = 16: 81