The largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively is
Question
(a) 17
(b) 11
(c) 34
(d) 45
in progress
0
Class 10 Maths
3 years
2021-12-17T16:00:15+00:00
2021-12-17T16:00:15+00:00 1 Answer
10 views
Enlightened 0
Answer ( 1 )
Answer: a
Explanation:(a); [Hint. Algorithm
398 – 7 – 391; 436 – 11 = 425; 542 – 15
= 527; HCF of 391, 425, 527 = 17]